Perimeter Made Simple : With Word Problems For Class 4th,5th [2]

Concepts of perimeter:

FOR CLASS 4TH AND 5TH

DEFINATION: PERIMETER is the length of the boundary of a plane figure.

FORMULAS :

1) Perimeter of a given shape = the sum of the length of all sides of the given shape.
2)Perimeter of a rectangle = 2*(L+B)
3)Perimeter of a square = 4*S
4)Perimeter of an equilateral triangle = 3*S

BASIC SUMS BASED ON PERIMETER LEVEL -2
SESSION – 2

Q1 ]. Find the perimeter .

1st part

SOLUTION : 1st part

Given that :
Length = L = 6cm
Breadth = B = 4cm
Perimeter of rectangle = ?

Perimeter of rectangle = P = 2 * (L + B )
P = 2 * ( 6 + 4)
P = 2 * 10
P = 20 cm

2nd part

SOLUTION : 2nd part

Given that :

Side = S = 3cm
Perimeter of the square = P = ?

Perimeter of the square = 4 * S = 4 * 3 = 12cm

3rd part

SOLUTION : 3rd part

Given that :

Side = S = 500m
Perimeter of an equilateral triangle = P = 3 * S

P = 3 * 500 = 1500 m

4th part

SOLUTION : 4th part

Given that :

Side = S = 44.9cm
Perimeter of square = P = ?

P = 4 * S = 4 * 44.9 = 179.6cm

5th part

SOLUTION : 5th part

Given that :

Length = L = 22.5 cm
Breadth = B = 18.9 cm
Perimeter of rectangle = P = ?

Perimeter of rectangle = 2 * ( L + B )
P = 2 * ( 22.5 + 18.9 )
P = 2 * 41.1 = 82.8 cm

6th part

SOLUTION : 6th part

Given that :

Side = S = 14.5 cm
Perimeter of an equilateral triangle = P = ?

P = 3 * S = 3 * 14.5 = 43.5 cm

7th part

SOLUTION : 7th part

Given that :

Length = L = 400 m
Breadth = B = 200 m
Perimeter of rectangle = P = ?

P = 2 * ( L + B ) = 2 * ( 400 + 200 )
P = 2 * ( 600 ) = 1200 m

8th part

SOLUTION : 8th part

Given that :

Length = L = 162 cm
Breadth = B = 83 cm
Perimeter of rectangle = P = ?

P = 2 * ( L + B )
P = 2 * ( 162 + 83 ) = 2 * ( 245 ) = 490 cm

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