KNOWING OUR NUMBERS
SIMPLE PRACTICE WORKSHEET – 1
CLASS 4th, 5th AND 6th
WITH SOLUTIONS GIVEN BELOW
Q.1) Write the expanded form of each of the following:
(a) 183576152
(b) 7898001
(c) 1100948
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Q.2) Write the successor of each of the following:
(a) 7998899
(b) 15096789
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Q.3) Write the predecessor of each of the following:
(a) 6700000
(b) 10000000
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Q.4) Compare the following using >, < or =.
(a) 5679834 and 5673834
(b) 6780009 and 6708900
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Q.5) Rewrite the following numbers in the Indian and the International systems of numeration using commas (,):
(a) 54693045
(b) 67613984
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Q.6)Round off the following numbers:
(a) 3934555 to the nearest ten
(b) 69 to the nearest hundred
(c) 1006 to the nearest thousand
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Q.7) Write the Roman numeral for each of the following:
(a) 81
(b) 94
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Q.8) Solve the following and write the answers in Roman numerals:
(a) XCIV – XL
(b) LIX + XXXVI + IX
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Q.9) Write the Hindu – Arabic numerals for the following:
(a) CLIX
(b) CD
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Q.10) Estimate the difference by rounding off the numbers to the nearest hundred.
(a) 6258 – 3125
(b) 275 – 193
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Q.11) Estimate the sum by rounding off the numbers to the nearest ten.
(a) 23 + 687
(b) 2397 + 6587
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Q.12) A woman saves Rs. 561 every month. Estimate the amount of money saved by her in one year. ( Estimate to the nearest ten.)
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Q.13) A packet can hold 154 screws. Estimate the number of packets required to pack 38,45,952 screws. ( Estimate to the nearest ten and thousand, respectively. )
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Q.14) In a town, there are 5,106 men, 3,982 women and 2,016 children. Find the estimated population of the town by rounding off the numbers to the nearest hundred.
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SOLUTIONS :
1)(a) 183576152 = 100000000 + 80000000 + 3000000 + 500000 + 70000 + 6000 + 100 + 50 + 2
(b) 7898001 = 7000000 + 800000 + 90000 + 8000 + 1
(c) 1100948 = 1000000 + 100000 + 900 + 40 + 8
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2) (a) 7998899 = 7998899 + 1
= 79,98,900
(b) 15096789 = 15096789 + 1
= 1,50,96,790
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3) (a) 6700000 = 6700000 – 1
= 66,99,999
(b) 10000000 = 10000000 – 1
= 99,99,999
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4) (a) 56,79,834 > 56,73,834
(b) 67,80,009 > 67,08,900
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5)
(a) 54693045
5,46,93,045 = Indian
54,693,045 = International
(b) 67613984
6,76,13,984 = Indian
67,613,984 = International
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6)(a) 3934555 to the nearest ten = 3934560
(b) 69 to the nearest hundred = 100
(c) 1006 to the nearest thousand = 1000
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7) (a) 81 = LXXXI
(b) 94 = XCIV
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8) (a) XCIV – XL = LIV
94 – 40 = 54
(b) LIX + XXXVI + IX = CIV
59 + 36 + 9 = 104
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9) (a) 159
(b) 400
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10) (a) 6258 – 3125
Actual difference
6258 – 3125 = 3133
Estimated difference
6300 – 3100 = 3200
(b) 275 – 193
Actual difference
273 – 193 = 82
Estimated difference
300 – 200 = 100
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11) (a) 23 + 687
Actual sum
23 + 687 = 710
Estimated sum
20 + 690 = 710
(b) 2397 + 6587
Actual sum
2397 + 6587 = 8984
Estimated sum
2400 + 6590 = 8990
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12) Savings every month = Rs. 561
Savings one year ( 12 months ) = 561 * 12
= 6732
= 6730
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13) No. of screws a packet can hold = 154
Total no. of screws =38,45,952
The no. of packets required = 38,45,952 / 154
= 24,973.7
= 24,974
Nearest ten = 24970
Nearest thousand = 25000
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14) No. of men 5106 – estimated to nearest hundred = 5100
No. of women 3982 – estimated to hundred = 4000
NO. of children 2016 – estimated to hundred = 2000
5100 + 4000 + 2000 = 11,100
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