MATH

Three Dimensional Shapes Made Great : With Points For Class 5th,6th,7th,8th,9th,10th

POINTS TO REMEMBER RELATED TO THREE DIMENSIONAL SHAPES :CLASS 5TH, 6TH, 7TH, 8TH, 9TH & 10TH READ : REPEAT : LEARN MUST KNOW THESE POINTS : 1) An object that occupies space is called a solid. 2) Shapes of solids are known as three – dimensional shapes. CUBOID3a) A cuboid has length, breadth and height.

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Mensuration Made Great : With Problems Questions For Class 8th,9th,10th[10]

WORD PROBLEMSRELATED TO MENSURATIONFOR CLASS 8TH , 9TH ,10TH Q 1.] A fixed open cylindrical metal tank having radius 4.9m and height 7.5m is to be painted from inside and outside . What will it cost at the rate of rupees 10 per m2 ? Solution : Fixed Open Cylindrical Metal Tank Given : Radius

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Mensuration Made Interesting : With Word Problems For Class 8th,9th,10th[9]

WORD PROBLEMS RELATED TO MENSURATION CLASS 8th, 9th AND 10th Q.1) An open cylindrical box of height 20cm and diameter 21cm is to be made using a cardboard. Find the area of the cardboard required to make the box. SOLUTION: OPEN CYLINDRICAL BOX Given: Height = 20cm Diameter = 21cm Radius = 21 / 2

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Mensuration Made Amazing : With Word Problems For Class 8th,9th,10th[8]

WORD PROBLEMS RELATED TO MENSURATION CLASS 8th, 9th, AND 10th Q.1 ) Six solid cubical stools with edge 65cm are to be painted red on all the sides. Find the quantity of paint required to paint 6 cubical stools if one can of paint is required to paint 11,700cm2 of area. SOLUTION: Given: No. of

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Math Quadrilateral Made Great : With Important Points For Class 6th.7th.8th.9th.10th[1]

POINTS TO KNOW : RELATED TO QUADRILATERAL CLASS 6th, 7th, 8th, 9th & 10th POINTS TO REMEMBER:- 1) ( i ) A quadrilateral which has exactly one pair of parallel sides is called a trapezium. ( ii ) A quadrilateral in which both pairs of opposite sides are parallel is called a parallelogram. ( iii

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Mensuration Made Simple : With Word Problems For Class 8th,9th,10th [6]

WORD PROBLEMS RELATED TO MENSURATION CLASS 8TH, 9TH & 10TH Q.1) Find the volume of the right circular cylinder whose curved surface area is 2640 cm2 and the circumference of the base is 66 cm. SOLUTION: circular cylinder Given : Curved surface area = LSA = 2640 cm2 Circumference = C = 66 cm Find

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